Copy the same economy and grow its scale. Watch the divisions everyone accepts narrow down to one.
When the economy is small, a few agents can break away and do better alone. As 🧑 people multiply, those escape routes get sliced away. Exactly one division survives in the end. It is the very division the market picks. The core shrinks to a point, as in the formula below.
For example, splitting 10 🍎 apples between 2 friends, almost any split works. Grow the group to 100 friends and the story changes. Unhappy friends can team up and cook up a new split. In the end only one split survives — one nobody can break away from.
In the symmetric economy, compare the core intervals for N=1 and N=2 replicas, and verify that the core width shrinks.
N=1:[4.583,5.417],width=0.833
N=2:[4.792,5.208],width=0.417
N=1→2: core width 0.833→0.417.Show proof
For N=1 the core is the individually rational segment of the contract curve (the diagonal), [4.583,5.417].
With N=2, new coalitions like (2,1) or (1,2) appear.
For instance, x11=5.42 was in the core for N=1 but is blocked for N=2 because coalition (1,2) can offer better.
The remaining core [4.792,5.208] is half as wide.
Show that the competitive allocation stays in the core for every N, and explain why this is one direction of the Debreu–Scarf limit theorem.
x∗=(5,5)∈core(N)∀N
CE (5,5) stays in the core for all N.Show proof
The competitive price is p1=1 with allocation x∗1=x∗2=(5,5). If a coalition S blocked with yS, every member strictly improves, but x∗i is budget-optimal so p⋅yi>p⋅ei; summing contradicts feasibility (same argument as the Ch. 13 exercise).
Hence x∗ is never blocked, for any N. Since the core shrinks to {x∗} as N→∞, core and competitive allocations coincide in the limit — the Debreu–Scarf theorem.