Watch the Prisoner's Dilemma repeated forever. The strategy punishes any betrayal forever.
Betray today and you gain a lot right now. But from tomorrow your partner betrays too, and the losses keep coming. How much you care about tomorrow decides the choice. Care enough about the future, and cooperation pays and holds. The boundary value comes from the formula below.
For example, say you and a 🧑 friend take turns lending a ⚽ ball every day. Hog the ball today and today is fun. But from tomorrow your friend never lends it to you. If you want to keep playing together, keeping today's promise wins.
In the infinitely repeated Prisoner's Dilemma with T=5, R=3, P=1, find the threshold δ∗ for grim-trigger strategies to sustain cooperation, and verify cooperation holds at δ=0.6.
At δ=0.6: VC​=0.43​=7.5, VD​=5+0.40.6​=6.5.
Since 7.5>6.5 there is no incentive to deviate — cooperation holds.
As δ shrinks, future punishment weighs less and deviation pays — which is why the curves cross at δ∗.
Explain via the δ∗ formula why a larger temptation payoff T makes cooperation harder to sustain, and compute δ∗ for T=7, R=3, P=1.
With T=7, δ∗=2/3>0.6 — cooperation collapses.Show proof
In δ∗=T−PT−R​, a larger T raises the one-shot gain from deviation (T−R). For T=7: δ∗=7−17−3​=64​=32​≈0.667.
With δ=0.6<2/3, deviation pays: VC​=7.5, VD​=7+0.40.6​=8.5. Bigger temptation demands more patience (higher δ) — the formal version of "patience buys cooperation."