← 3. Consumer Choice

Exercises

Problems to check your understanding of this chapter. The solutions are folded away — try them yourself first.

Easy

1Easy

With p1=2p_1 = 2, p2=1p_2 = 1, w=60w = 60, find the two intercepts and the slope of the budget line.

Bp,w={x≥0:p1x1+p2x2≤w}B_{p,w} = \{x \ge 0 : p_1 x_1 + p_2 x_2 \le w\}
Intercepts (30,60)(30, 60), slope −2-2 — the probe b=(15,30)b = (15, 30) sits on the budget line.
Show solution
  1. The x1x_1-intercept is w/p1=60/2=30w/p_1 = 60/2 = 30 and the x2x_2-intercept is w/p2=60/1=60w/p_2 = 60/1 = 60.

  2. The slope is −p1/p2=−2-p_1/p_2 = -2 — the opportunity cost of one unit of good 1 is two units of good 2.

Medium

2Medium

At p=(1,1)p = (1, 1), w=60w = 60 the bundle (30,30)(30, 30) lies on the budget line.

When p1p_1 rises to 22, is this bundle still affordable? Describe the geometric change of the budget line as well.

Show solution
  1. The original intercepts were (60,60)(60, 60). At p1=2p_1 = 2 only the x1x_1-intercept shrinks to 3030; the budget line rotates inward around the x2x_2-intercept.

  2. The bundle (30,30)(30, 30) now costs 2⋅30+30=90>602 \cdot 30 + 30 = 90 > 60, so it is no longer affordable. Bundles heavy in the now-expensive good are hit hardest — the geometry of the rotation made visible.

3Medium

With u(x1,x2)=x11/4x23/4u(x_1, x_2) = x_1^{1/4} x_2^{3/4}, p1=2p_1 = 2, p2=1p_2 = 1, w=80w = 80, find x1(p,w)x_1(p, w) and verify that doubling all prices and wealth leaves demand unchanged.

x1(p,w)=awp1x_1(p, w) = \frac{aw}{p_1}
a=1/4a = 1/4, p1=2p_1 = 2, w=80w = 80, λ=2\lambda = 2 — x1=10x_1 = 10 unchanged.
Show solution
  1. With a=1/4a = 1/4, x1=0.25⋅802=10x_1 = \frac{0.25 \cdot 80}{2} = 10.

  2. Doubling prices and wealth gives x1(2p,2w)=0.25⋅1604=10x_1(2p, 2w) = \frac{0.25 \cdot 160}{4} = 10 — the factor of 2 cancels between numerator and denominator. The point on the demand curve does not move.

Hard

4Hard

For λ>0\lambda > 0, prove the equality below, and deduce directly from the definition of the UMP that Walrasian demand x(p,w)x(p, w) is homogeneous of degree zero.

B(p,w)={x≥0:p⋅x≤w}B(p, w) = \{x \ge 0 : p \cdot x \le w\}
x(p,w)=arg⁡max⁡x∈B(p,w)u(x)x(p, w) = \arg\max_{x \in B(p, w)} u(x)
B(λp,λw)=B(p,w)B(\lambda p, \lambda w) = B(p, w)
Show solution
  1. x∈B(λp,λw)x \in B(\lambda p, \lambda w) means (λp)⋅x≤λw(\lambda p) \cdot x \le \lambda w.

    Since λ>0\lambda > 0, dividing by λ\lambda gives p⋅x≤wp \cdot x \le w, i.e. x∈B(p,w)x \in B(p, w).

    The converse is identical, so the two sets are equal.

  2. The UMP maximizes utility over the budget set, so equal sets give equal maximizers: x(λp,λw)=arg⁡max⁡B(λp,λw)u=arg⁡max⁡B(p,w)u=x(p,w)x(\lambda p, \lambda w) = \arg\max_{B(\lambda p, \lambda w)} u = \arg\max_{B(p, w)} u = x(p, w).

    x(λp,λw)=x(p,w)∀λ>0x(\lambda p, \lambda w) = x(p, w) \quad \forall \lambda > 0
  3. Scaling prices and wealth together leaves the budget set itself unchanged, so the choice cannot change either — the geometric reason behind the degree-zero homogeneity of demand.