The Representative Consumer

This scene asks whether many people can act as one. Shuffle money between two people with identical tastes.

However the money is split, aggregate demand never moves. What one person loses, the other gains exactly. Only the total amount of money matters. Then a representative consumer exists. The whole market computes like one imaginary person.

For example, twin brothers split a πŸ’° allowance of 12,000 won. The older may take 8,000 and the younger 4,000. Swap the split, and the 🍎 apples they buy stay the same. Only the total matters, not who holds what.

X1(p1)=aWp1,W=w1+w2X_1(p_1) = \frac{aW}{p_1}, \quad W = w_1 + w_2
vi(p,wi)=ai(p)+b(p) wi(Gorman)v_i(p, w_i) = a_i(p) + b(p)\,w_i \quad \text{(Gorman)}

Part of these learning paths

Examples & Exercises

Two identical-taste Cobb-Douglas consumers with a=1/2a = 1/2, total wealth W=120W = 120, p2=1p_2 = 1.

Compute aggregate demand X1X_1 at p1=1p_1 = 1 for the wealth splits s=0.2s = 0.2 and s=0.8s = 0.8, and verify they coincide regardless of the distribution.

X1=aw1p1+aw2p1=aWp1X_1 = \frac{a w_1}{p_1} + \frac{a w_2}{p_1} = \frac{aW}{p_1}
s=0.2:β€…β€Š12+48=60,s=0.8:β€…β€Š48+12=60s = 0.2:\; 12 + 48 = 60, \qquad s = 0.8:\; 48 + 12 = 60
a=1/2a = 1/2, W=120W = 120, s=0.2s = 0.2 β€” exactly on top of the ghost curve (s=0.5s = 0.5).
Show proof
  1. With s=0.2s = 0.2, w1=24w_1 = 24 and w2=96w_2 = 96, so X1=0.5β‹…24+0.5β‹…96=12+48=60X_1 = 0.5 \cdot 24 + 0.5 \cdot 96 = 12 + 48 = 60.

  2. With s=0.8s = 0.8, w1=96w_1 = 96 and w2=24w_2 = 24, so X1=48+12=60X_1 = 48 + 12 = 60 β€” the individual demands swap, but the sum is unchanged.

  3. In general ss cancels in X1=asW/p1+a(1βˆ’s)W/p1=aW/p1X_1 = a sW/p_1 + a(1-s)W/p_1 = aW/p_1. Aggregate demand is pinned down by total wealth WW alone, so a single consumer with wealth WW (Cobb-Douglas, parameter aa) is this economy's "representative consumer".

Verify that Cobb-Douglas indirect utility v(p,w)=b(p) wv(p, w) = b(p)\,w, with b(p)=aa(1βˆ’a)1βˆ’a/(p1ap21βˆ’a)b(p) = a^a (1-a)^{1-a} / (p_1^a p_2^{1-a}), is of the Gorman form with a common b(p)b(p),

and use Roy's identity to find X1X_1 for a=0.6a = 0.6, W=150W = 150, s=0.3s = 0.3, p1=2p_1 = 2.

vi(p,wi)=0β‹…Ξ±i(p)+b(p) wi(Gorman,Β commonΒ b)v_i(p, w_i) = 0 \cdot \alpha_i(p) + b(p)\,w_i \quad \text{(Gorman, common } b\text{)}
X1=0.6β‹…1502=45X_1 = \frac{0.6 \cdot 150}{2} = 45
a=0.6a = 0.6, W=150W = 150, s=0.3s = 0.3, p1=2p_1 = 2 β€” X1=45X_1 = 45, distribution-free.
Show proof
  1. Plugging Cobb-Douglas demand x(p,w)=(aw/p1,(1βˆ’a)w/p2)x(p, w) = (aw/p_1, (1-a)w/p_2) into utility gives v(p,w)=wβ‹…aa(1βˆ’a)1βˆ’a/(p1ap21βˆ’a)=b(p) wv(p, w) = w \cdot a^a (1-a)^{1-a} / (p_1^a p_2^{1-a}) = b(p)\,w. Both consumers share the same aa, hence the same b(p)b(p): the Gorman form with Ξ±i(p)=0\alpha_i(p) = 0.

  2. Roy's identity: x1i=βˆ’βˆ‚vi/βˆ‚p1βˆ‚vi/βˆ‚w=βˆ’bβ€²(p)wib(p)=awip1x_1^i = -\frac{\partial v_i / \partial p_1}{\partial v_i / \partial w} = -\frac{b'(p) w_i}{b(p)} = \frac{a w_i}{p_1} (the last equality follows by differentiating the formula for b(p)b(p)).

  3. Summing, the common b(p)b(p) in the denominator gives X1=βˆ’bβ€²(p)W/b(p)=aW/p1=0.6β‹…150/2=45X_1 = -b'(p)W / b(p) = aW/p_1 = 0.6 \cdot 150 / 2 = 45 β€” the individual wealths w1=45w_1 = 45, w2=105w_2 = 105 contribute only through 13.5+31.5=4513.5 + 31.5 = 45.

5. Aggregate Demand